The electric fields ue to charge distribution is given by E=K/r2 exp(-4r)r cap where K is constant in SI unit s,The total charge (in colunb) in over all space is equal to

For spherically symmetrical charge distribution, electric field at a distance r from the centre of sphere is vec(E)=kr^(7) vec(r) , where k is a constant. What will be the volume charge density at a distance r from the centre of sphere?

The electrostatic force between two charges Q_(1) and Q_(2) at separation r is given by F= (K.Q_(1)Q_(2))/(r^(2)) The constant K

Let a total charge 2Q be distributed in a sphere of radius R, with the charge density given by , rho(r)=kr , where r is the distance from the centre. Two charge A and B, of –Q each, are placed on diametrically opposite points, at equal distance, a from the centre. If A and B do not experience any force, then:

Charge is distributed within a sphere of radius R with a volume charge density p(r)=(A)/(r^(2))e^(-2r//a), where A and a are constants. If Q is the total charge of this charge distribution, the radius R is :

A solid sphere of radius R has a charge Q distributed in its volume with a charge density rho=kr^a , where k and a are constants and r is the distance from its centre. If the electric field at r=(R)/(2) is 1/8 times that r=R , find the value of a.

A solid non conducting sphere of radius R has a non-uniform charge distribution of volume charge density, rho=rho_(0)r/R , where rho_(0) is a constant and r is the distance from the centre of the sphere. Show that : (i) the total charge on the sphere is Q=pirho_(0)R^(3) (ii) the electric field inside the sphere has a magnitude given by, E=(KQr^(2))/R^(4)

A charge +Q , is uniformaly distributed within a sphere of radius R. Find the electric field, due to this charge distribution, at a point distant r form the centre of the spehre where : (i) 0 lt r lt R and (ii) r gt R

The electric field on two sides of a large charged plate is shown in figure. The charge density on the plate in SI units is given by (epsilon_0 is the permittivity of free space in SI units).

The electric field in a region of space is given by E= 5i + 2j N//C . The electric flux due to this field through an area 2m^(2) lying in the Yz plane, in S.I. units, is

The angular frequency of the damped oscillator is given by omega=sqrt((k)/(m)-(r^(2))/(4m^(2))) ,where k is the spring constant, m is the mass of the oscillator and r is the damping constant. If the ratio r^(2)//(m k) is 8% ,the change in the time period compared to the undamped oscillator