A stone is dropped from 125m height,If g=10m/s2 ,what will be the distnace travelled in first and last second of its motion.

A stone is dropped from the top of a tower of height 125 m. The distance travelled by it during last second of its fall is (g=10 ms^(-2))

An object that is dropped freely from rest travels for 5 seconds.What is the distance travelled in the last 2 seconds of its journey.

A ball is dropped from the roof of a tower height h . The total distance covered by it in the last second of its motion is equal to the distance covered by it in first three seconds. The value of h in metre is (g=10m//s^(2))

A ball is dropped from the roof of a tower height h . The total distance covered by it in the last second of its motion is equal to the distance covered by it in first three seconds. The value of h in metre is (g=10m//s^(2))

A body is projected with a velocity 60 ms^(-1) vertically upwards the distance travelled in last second of its motion is [g=10 ms^(-1)]

A ball is dropped from a height of 45 m from the ground. The coefficient of restitution between the ball and the ground is 2/3 . What is the distance travelled by the ball in 4th second of its motion. Assume negligible time is spent in rebounding. Let g= 10 ms^(2)

A particle is dropped from the top of a high building 360 m. The distance travelled by the particle in ninth second is (g=10 m//s^(2))

A stone at rest is dropped from a height and falls freely under gravity. Calculate the distance covered by it in the first two seconds. (g = 9.8 m s^(-2) )

A stone is dropped from the top of a tower and travels 24.5 m in the last second of its journey. The height of the tower is

A stone falls freely from rest and the total distance covered by it in last second of its motion equals the distance covered by it in the first 3s of its motion. How long the stone will remain in the air?