The maximum number of electrons in a subshell is given by the

A (2l+1)
B 2(2l+1)
C (2l+1)2
D 2(2l+1)2

STATEMENT-1 : The maximum number of electrons in subshell p is 6. and STATEMENT -2 : The maximum number of electrons in a subshell isgiven by ( 4l +2 ) , where l is the azimuthal quantum number and for p-subshell l=1 .

The maximum number of electrons that can be present in an orbit with s = +1/2 and l=2

Maximum electron in 1^(st) shell having m_(l) =2 will be

{:(,"ColumnI",,"ColumnII"),((A),"Number of orbitials in the" n^(th)"shell",(P),2(2l+1)),((B),"Maximum number of electrons in a subshell",(Q),n),((C),"Number of subshell in" n^(th)"shell",(R),2l+1),((D),"Number of orbitals in a subshell",(S),n^(2)):}

Out of the following the correct statement(s) is/are , (a) Number of subshells present in M-shell is equal to 3 (b) maximum number of electrons present in L shell is equal to 8 (c) number of electron present in subshell is 3(2l + 1), (d) Cu^+ is paramagnetic

If n and l are respectively the principal and azimuthal quantum numbers , then the expression for calculating the total number of electrons in any energy level is : (a) underset(l=0)overset(l=n)sum2(2l+1) (b) underset(l=1)overset(l=n)sum2(2l+1) (c) underset(l=0)overset(l=n)sum2(2l+1) (d) underset(l=0)overset(l=n-1)sum2(2l+1)

The quantum number of four electrons are given below: n=4,l=2,m_(l)=-2,m_(s)=-1//2 n=3,l=2,m_(l),m_(s)=+1//2 n=4,l=1,m_(l)=0,m_(s)=+1//2 n=3,l=1,m_(l)=1,m_(s)=-1//2 The correct order of their increasing energies will be:

Consider atoms H, He^(+), Li^(++) in their ground states. If L_(1), L_(2) and L_(3) are magnitude of angular momentum of their electrons about the nucleus respectively then: A. L_(1)=L_(2)=L_(3) B. L_(1) gt L_(2) gt L_(3) C. L_(1) lt L_(2) lt L_(3) D. L_(1)=L_(2)=L_(3)

The quantum number of electrons are given below: Arrange then in order of increasing energies a. n= 4,l= 2,m_(1)= -2, m_(s)= -(1)/(2) b. n= 3,l= 2,m_(1) = 1, m_(s)= +(1)/(2) c. n= 4,l= 1,m_(1) = 0, m_(s)= +(1)/(2) e.n= 3,l= 2,m_(1)= -2, m_(s)= +(1)/(2) f. n= 4,l= 1,m_(1) = +1, m_(s)= +(1)/(2)

The quantum number of four electrons are given below: I. n=4,l=2,m_l=-2,m_s=-1/2 II. n=3,l=2,m_l=1,m_s=+1/2 III. n = 4 , l =1 ,m _l=0 ,m_s=+1/2 IV. n=3,l=1,m_l=1,m_s=-1/2 The correct order of their increasing energies will be