If -2 < x < 3 then :
( a ) `4 < x^2 < 9`
( b ) `0 le | x | < 5`
( c ) `0 le x^2 < 9`
( d ) None

If 0 le x le pi/2 then

y - 2x le 1, x + y le 2, x ge 0, y ge 0

x + 2y le 40, 2x + y le 40, x ge 0, y ge 0

2x + y le 6, x + 2y le 8, x ge 0, y ge 0

If f (x) =x ^(2) -6x + 9, 0 le x le 4, then f(3) =

Maximize z = 7x_(1) + 3x_(2) by graphical method Subjecto to x_(1) + 2x_(2) ge 3 x_(1) + x_(2) le 4 0 le x_(1) le (5)/(2) and 0 le x_(2) le (3)/(2)

Let the area of the region {(x, y): 0 le x le 3 , 0 le y le min{x^2+ 2, 2x 2}} be A. Then 12A is equal to _____.

If f (x) =x ^(2) -6x +5,0 le x le 4 then f (8)=

If f(x) {:(=-x^(2)", if " x le 0 ), (= 5x - 4 ", if " 0 lt x le 1 ),(= 4x^(2)-3x", if " 1 lt x le 2 ):} then f is

Solve the following : (a) 1 le |x-2| le 3 " (b) "0 lt |x-3|le 5 (c ) |x-2|+|2x-3|=|x-1| " (d) " |(x-3)/(x+1)| le1