the emf of the cell M|metal nitrate(0.01M)||metal nitrate (0.1M)|M is found to be 0.0591V at 298K. the valency of metal in metal nitrate is

Nitrates of all metals are

The EMF of the cell M|M^(n+)(0.02M) ||H^(+)(1M)|H_(2)(g) (1atm)Pt at 25^(@)C is 0.81V . Calculate the valency of the metal if the standard oxidation potential of the metal is 0.76V .

1.0 g of metal nitrate gave 0.86 g of metal sulphate. Calculate the equivalent weight of metal.

1.0 g of metal nitrate gave 0.86 g of metal carbonate. Calculate the Equivalent weight of metal.

25 gm of a metal is deposited on cathode during the electrolysis of metal nitrate solution by a current of 5 apm pssing for 4 hour if atomic weight of the metal is 100 The valency of metal in metal intrates is

To find the standard potential of M^(3+)//M electrode , the following cell is constituted : Pt|M|M^(3+((.001moLL^(-1)|| Ag ^(+) ((0.01moLL^(-1))| Ag. The emf of the cell is found to be 0.421 volt at 298 K. The standard potential of half reaction M^(3+)+ 3e^(-) to M at 298 K will be : (Given E_(Ag^(+)//Ag^(@) at 298 K = 0.80 Volt)

0.452 g of a metal nitrate gave 0.4378 g of its metal sulphate. Calculate the equivalent weight of the metal.

A bivalent metal has an equivalent mass of 32. The molecular mass of the metal nitrate is

A metal nitride M_(3)N_(2) contains 28 % of nitrogen. The atomic mass of metal M is

Alkaline earth metal nitrates on heating decompose to give :