The equilibrium constant for the reaction `SO_(3(g))rarr SO_(2(g))+(1)/(2)O_(2(g))` is `0.15` at `900K`. Then `K` for:
`2SO_(2(g))+O_(2(g))rarr2SO_(3)(g)`
`0.15`
`0.0225`
`44.44`
`0.3`

The equilibrium constant of the reaction, SO_(3)(g) hArr SO_(2)(g)+1//2 O_(2)(g) is 0.15 at 900 K . Calculate the equilibrium constant for 2SO_(2)(g)+O_(2)(g) hArr 2SO_(3)(g)

The equilibrium constant for the reation, SO_3(g) hArr SO_2( g) +(1)/(2) O_2(g) is K_c= 4.9 xx 10^(-2) The value of K_c for the reaction 2SO_2(g) + O_2(g) hArr 2SO_3(g), will be

The equilibrium constant for the given reaction: SO_(3(g))hArrSO_(2(g))+1//2O_(2(g)) , (K_(c)=4.9xx10^(-2)) The value of K_(c) for the reaction: 2SO_(2(g))+O_(2(g))hArr2SO_(3(g)) , will be :

Write the equilibrium constant expression for the following reactions : 2SO_3(g)hArr 2SO_2(g) +O_2(g)

For the reaction 2SO_(3)(g)hArr2SO_(2(g))+O_(2(g)) (K_(C))/(K_(p)) will be :-

For the system S (s) + O_(2)(g) rarr SO_(2)(g) ?

The reaction SO_(2)(g) +1//2O_(2)(g) rarr SO_(3)(g) should be

Give the mathematical expression for the equlibrium constant K_(c) for the reaction. 2SO_(3)(g)hArr2SO_(2)(g)+O_(2)(g)

Which one is the correct representation for the reaction 2SO_(2)(g)+O_(2)(g) hArr 2SO_(3)(g)

The equilibrium constant of the reaction SO_(2)(g) + 1//2O_(2)(g)hArrSO_(3)(g) is 4xx10^(-3)atm^(-1//2) . The equilibrium constant of the reaction 2SO_(3)(g)hArr2SO_(2)(g) + O_(2)(g) would be: