Equilibrium constants are given for various reactions:
1)`N_(2)+3H_(2)hArr2NH_(3)`; `K_(1)`
2)`N_(2)+O_(2)hArr2NO`; `K_(2)`
3)`H_(2)+(1)/(2)O_(2)hArrH_(2)O`; `K_(3)`.
Then the equilibrium constant for the following reaction (4) is
4)`2NH_(3)+(5)/(2)O_(2)hArr2NO+3H_(2)O`

The following equilibria are given by : N_(2)+3H_(2) hArr 2NH_(3), K_(1) N_(2)+O_(2) hArr 2NO,K_(2) H_(2)+(1)/(2)O_(2) hArr H_(2)O, K_(3) The equilibrium constant of the reaction 2NH_(3)+(5)/(2)O_(2)hArr 2NO +3H_(2)O in terms of K_(1) , K_(2) and K_(3) is

Given N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g),K_(1) N_(2)(g)+O_(2)(g)hArr2NO(g),K_(2) H_(2)(g)+(1)/(2)O_(2)hArrH_(2)O(g),K_(3) The equilibrium constant for 2NH_(3)(g)+(5)/(2)O_(2)(g)hArr2NO(g)+3H_(2)O(g) will be

Given N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g),K_(1) N_(2)(g)+O_(2)(g)hArr2NO(g),K_(2) H_(2)(g)+(1)/(2)O_(2)hArrH_(2)O(g),K_(3) The equilibrium constant for 2NH_(3)(g)+(5)/(2)O_(2)(g)hArr2NO(g)+3H_(2)O(g) will be

The equilibrium constant of the following are : " " {:(N_2+3H_2hArr 2NH_3, K_1),(N_2+O_2hArr 2NO , K_2) , (H_2+(1)/(2) O_2 to H_2O , K_3) :} The equilibrium constant (K) of the reaction : 2NH_3+(5)/(2) O_2 overset(k) hArr 2NO +3H_2O, will be (a) K_1K_3^(3) //K_2 (b) K_2K_3^(3) //K_1 (c) K_2K_3//K_1 (d) K_2^(3) K_3//K_1

The equilibrium constant for the reaction CaSO_(4).H_(2)O(s)hArr CaSO_(4).3H_(2)O(s)+2H_(2)O(g) is equal to

Equilibrium constant for the reactions, 2 NO+O_(2)hArr2 NO_(2) "is" K_(c_(1) , NO_(2)+SO_(2)hArrSO_(3)+NO "is" L_(C_(2) and 2 SO_(3)hArr2 SO_(2)+O_(2) "is" K_(c_(3) then correct reaction is:

The equilibrium constant of the following reactions at 400 K are given: 2H_(2)O(g) hArr 2H_(2)(g)+O_(2)(g), K_(1)=3.0xx10^(-13) 2CO_(2)(g) hArr 2CO(g)+O_(2)(g), K_(2)=2xx10^(-12) Then, the equilibrium constant K for the reaction H_(2)(g)+CO_(2)(g) hArr CO(g)+H_(2)O(g) is

The relation between K_(p) and K_(c) is K_(p)=K_(c)(RT)^(Deltan) unit of K_(p)=(atm)^(Deltan) , unit of K_(c)=(mol L^(-1))^(Deltan) H_(3)ClO_(4) is a tribasic acid, it undergoes ionisation as H_(3)ClO_(4) hArr H^(o+)+H_(2)ClO_(4)^(-), K_(1) H_(2)ClO_(4)^(-) hArr H^(o+)+HClO_(4)^(2-), K_(2) HClO_(4)^(2-) hArr H^(o+)+ClO_(4)^(3-), K_(3) Then, equilibrium constant for the following reaction will be: H_(3)ClO_(4) hArr 3H^(o+)+ClO_(4)^(3-)

Consider the reaction, NO_(2) rarr 1/2N_(2) + O_(2),K_(1) , N_(2)O_(4) rarr 2NO_(2) , K_(2) Give the equilibrium constant for the formation of N_(2)O_(4) "from" N_(2) "and" O_(2) .

At 25^(@) C the equilibrium constant K,and K_(2) of two reaction are 2NH_(3)hArrN_(2)+3H_(2) ,K_(1) (1)/(2)N_(2)+(3)/(2)H_(2)hArrNH_(3),K_(2) The relation b//w two equilibrium constant is :-