In Buckminster fullerene, the number of six membered rings and five membered rings respectively are

A 20, 12
B 12, 20
C 6, 12
D 12, 6

C_(60) contains 'x' five membered rings & 'y' six memebered Then :

How many of the following statements are correct regarding allotropes of carbon: (a) Graphite is not a good conductor of electicity in perpendicular direction of layers at ordinary temperatures. (b) Coke is the impure form of carbon. ( c) Anthracite is the purest form of carbon. (d) Buckminister fullerence contains 12 five membered rings and 20 six-membered rings. (e) Diamond is a good conductor of heat. (f) Graphite is diamagnetic in nature. (g) Graphite is thermodynamically more stable than diamond

The number of six membered carbon rings in the structure of Buckminsterfullerene (i.e. C_60 )is .

Consider a prototypical fullerene, C_(60) Let, a = Number of 5 -membered rings: b = Number of 6 -membered rings c = Number of pi bonds in C_(60) Find the value of (3a-2b+c)

Intramolecular aldol condensation : The aldol condensation also offer a convenient way to synthesize molecules with five and six membered ring.This can be done by an intramolecular aldol condensation using a dialdehyde, a keto aldehyde or a diketone as the substrate.The major product is formed by the attack of the enolate from the ketone side of the molecule that adds to the aldehyde group.The reason the aldehyde group undergoes addition preferentially may arise from the greater reactivity of aldehyde towards nucleophilic addition.In reaction of this type five membered rings from far more readily than seven membered rings and six membered rings are more favourable than four or eight membered rings when possible. The true statement about the major product of CH_3-oversetOoverset(||)C-CH_2-CH_2-CH_2-CH_2-oversetoverset(O)(||)C-H in reaction with aq.NaOH followed by heating is.

Calculate the number of electrons , protons and neatrons in the following species a. ._6C^(13) b. ._6C^(12)

Assertion : Fullerenes are the only pure form of carbon. Reason : It contains twenty, five membered rings and twelve, six membered rings.

The number of terrahedral and octahedral holes in a hexagonal primitive unit cell are respectively: (a)8,4 (b)6,12 (c)2,1 (d)12,6

Three numbers are in the ratio 1:2:3 and their HCF is 6, the numbers are (a) 4, 8, 12 (b) 5, 10, 15 (c) 6, 12, 18 (d) 10, 20, 30