`lim_(r rarr1)pi r^2`

lim_(x rarr0)(sin^2x)/(1-cosx)

The value of lim_(xrarr1)Sigma_(r=1)^(10)=(x^(r )-1^(r ))/(2(x-1)) is equal to

lim_(x rarr -pi) |x+pi|/sinx is

The value of lim_(x rarr a) (2- a/x)^(tan ((pi x)/(2a))) is:

The value of lim_(x rarr 1)(2-x)^(tan((pix)/2)) is (a) e^(-2/pi) (b) e^(1/pi) (c) e^(2/pi) (d) e^(-1/pi)

If p , r , s gt 0 then lim_(x rarr oo)((p^(1/x)+q^(1/x)+r^(1/x)+s^(1/x))/4)^(3x)

lim_( r to 0) pir^(2)

Evaluate : lim_(x rarr1) (logx /(x - 1))

lim_(x rarr0)(1+2x)^(5/x)

Let f(x)=lim_(n rarr oo)(x^(2n-1)+ax^(2)+bx)/(x^(2n)+1). If f(x) is continuous for all x in R then find the values of a and b.