In triangle `ABC` ,if `y=x+1&y=2x+3` are altitude through A & angle bisector of B respectively.If vertex `C=(3,4)` then equation of median through `C` is

In triangle ABC, the co-ordinates of vertices A, B and C are (4, 7), (-2, 3) and (0, 1) respectively. Find the equation of median through vertex A. Also, find the equation of the line through vertex B and parallel to AC.

In a triangle ABC, if A is (1, 2) and the equations of the medians through B and c are x+ y= 5 and x= 4 respectively then B must be:

Consider a triangle with vertices A(1,2),B(3,1), and C(-3,0)dot Find the equation of altitude through vertex Adot the equation of median through vertex Adot the equation of internal angle bisector of /_Adot

In a triangle A B C , if A is (2,-1),a n d7x-10 y+1=0 and 3x-2y+5=0 are the equations of an altitude and an angle bisector, respectively, drawn from B , then the equation of B C is (a) a+y+1=0 (b) 5x+y+17=0 (c) 4x+9y+30=0 (d) x-5y-7=0

If the coordinates of the vertices of triangle A B C are (-1,6),(-3,-9) and (5,-8) , respectively, then find the equation of the median through Cdot

If the coordinates of the vertices of triangle A B C are (-1,6),(-3,-9) and (5,-8) , respectively, then find the equation of the median through Cdot

In triangle A B C , the equation of the right bisectors of the sides A B and A C are x+y=0 and y-x=0 , respectively. If A-=(5,7) , then find the equation of side B Cdot

In a DeltaABC, A = (2,3) and medians through B and C have equations x +y - 1 = 0 and 2y - 1 = 0 Equation of median through A is

Consider a triangle ABC with vertex A(2, -4) . The internal bisectors of the angle B and C are x+y=2 and x- 3y = 6 respectively. Let the two bisectors meet at I .if (a, b) is incentre of the triangle ABC then (a + b) has the value equal to

Let A B C be a triangle. Let A be the point (1,2),y=x be the perpendicular bisector of A B , and x-2y+1=0 be the angle bisector of /_C . If the equation of B C is given by a x+b y-5=0 , then the value of a+b is (a) 1 (b) 2 (c) 3 (d) 4