`(x^(2)+xy)dy=(x^2+y^(2))dx`

(x^2y^3+xy)dy=dx

Solve the differential equations x^(2)dy-(x^(2)+xy-2y^(2))dx=0

Equation of curve passing through (1,1) & satisfyng the differential equation (xy^(2)+y^(2)+x^(2)y+2xy)dx+(2xy+x^(2))dy=0 is

(1-x^(2))(dy/dx)+xy=xy^(2)

If (y^(3)-2x^(2)y)dx+(2xy^(2)-x^(3))dy=0, then the value of xysqrt(y^(2)-x^(2)), is

The solution of the differential equation y^(2)dx+(x^(2)-xy + y^(2))dy = 0 is

The differential equations of all circle touching the x-axis at orgin is (a) (y^(2)-x^(2))=2xy((dy)/(dx)) (b) (x^(2)-y^(2))(dy)/(dx)=2xy ( c ) (x^(2)-y^(2))=2xy((dy)/(dx)) (d) None of these

Solve (x^(2) + y^(2))(dy)/(dx) = 2xy

Solve the differential equation : (dy)/(dx)=(x^(2)-y^(2))/(xy) .

Solve the differential equation , (xy^(2) + x) dx + (x^(2)y +y)dy=0