The position of a particle moving along the y axis is given as `y=2t-t^2` , where y is in m and t is in s. The time when particle attains maximum in positive direction is

The position of a particle moving along the y-axis is given as y=3t^(2)-t^(3) where y is in , metres and t is in sec.The time when the particle attains maximum positive y position will be

The position of the particle moving along x-axis is given by x=2t-3t^(2)+t^(3) where x is in mt and t is in second.The velocity of the particle at t=2sec is

Position of particle moving along x-axis is given as x=2+5t+7t^(2) then calculate :

The position of the particle moving along Y -axis is given as y=At^(2)-Bt^(3) , where y is measured in metre and t in second. Then, the dimensions of B are

The position of a particle is given by x=2(t-t^(2)) where t is expressed in seconds and x is in metre. The particle

The position of a particle with respect to time t along y-axis is given by : y = 12t^2 – 2t^3 , where, y is in metres and t is in seconds. When the particle achieves maximum speed, the position of the particle would be

The position of a particle moving along x-axis varies eith time t as x=4t-t^(2)+1 . Find the time interval(s) during which the particle is moving along positive x-direction.

The position of a particle is given by x=2(t-t^(2)) where t is expressed in seconds and x is in metre. The acceleration of the particle is

Position of a particle moving along x-axis is given by x=2+8t-4t^(2) . The distance travelled by the particle from t=0 to t=2 is:-