Two force vectors have magnitude "6N" and "8N" Their resultant may have a magnitude: (A) 2N (B) 10N (c) 14N (D) 16N

Two vectors inclined at an angle theta have magnitude 3 N and 5 N and their resultant is of magnitude 4 N . The angle theta is

The resultant of two vectors is perpendicular to first vector of magnitude 6N. If the resultant has magnitude 6sqrt(3)N , then magnitude of second vector is

Two forces of magnitude 1 N and 13 N resultant of magnitude 6sqrt(5)N, then that is the angle between two forces.

Two forces 4N and 3N act at an angle of 90o.The magnitude of their resultant is (a)4N (b)3N (c)5N (d)7N

Two forces are such that the sum of their magnitudes is 18N ," the resultants sqrt(228) when they are at 120^(@) then magnitude of largest force is

Two force vectors each having magnitude 6N are oriented as 30^(@) from positive of x-axis and other at 90^(@) with the same axis. Find out their magnitude along with position from positive of x-axis :-

Two forces are such that the sum of their magnitudes is 18N and their resultant is 12 N which is perpendicular to the smaller force. Then the magnitude of the forces are

Two force vectors vecF_1 and vecF_2 , each of magnitude 10 N act at a point at an angle of 60°. The magnitude of resultant force vector is

The four pairs of force vectors are given, which pairs of force vectors cannot be added to give a resultant vector of magnitude 10N ?