How would you establish an instantaneous displacement current of 12.0A in the space between the two parallel plates of `1muF` capacitor?

you are given a 2 muF parallel capacitor. How would you establish an instantaneous displacement current in 1mA iin the space between its plates?

The displacement current is produced across the gap between the two plates of a capacitor, when the charge on the capacitor

Two parallel plate air capacitors have their plate areas 100 and 500 cm^(2) respectively. If they have the same charge and potential and the distance between the plates of the first capacitor of 0.5 mm, what is the distance between the plates of second capacitor ?

A capacitor ,made of two parallel plates,each of area A and separaion d,is being charged by an external a.c. surce.show that the displacement current inside the capacitor is the same as the current charging the capacitor.

Figure shows two identical capacitors C_1 and C_2 each of 1 mu F capacitance connected to a battery of 6 V. initially switch S is closed. After sometime S is left open and dielectric slab of dielectric constant k = 3 are inserted to fill completely the space between the plates of the two capacitors. How will the potential difference between the plates of the capacitors be affected after the slabs are inserted?

Figure shows two identical capacitors C_1 and C_2 each of 1 mu F capacitance connected to a battery of 6 V. initially switch S is closed. After sometime S is left open and dielectric slab of dielectric constant k = 3 are inserted to fill completely the space between the plates of the two capacitors. How will the Charge between the plates of the capacitors be affected after the slabs are inserted?

Two parallel plate capacitors A and B have the same separation d= 8.85xx10^-4m between the plates. The plate area of A and B are 0.04m^2 and 0.02m^2 respectively. A slab of dielectric constant (relative permittivity) K=9 has dimensions such that it can exactly fill the space between the plates of capacitor B. A is then charged to a potential difference of 110V. Calculate the capacitance of A and the energy stored in it.

Prove that if a conducting slab wholly fills the space between the plates, then the capacitance of a parallel plate capacitor is infinity.

Keeping the voltage of the charging source constant, what would be the percentage change in the energy stored in a parallel plate capacitor, if the separation between in plates were to be decreased by 10% ?

In a parallel plate capacitor with air between the plates, each has an area of 6xx10^-3m^-2 and the distance between the platesw is 3mm. Calculate the capacitance of the capacitor, If this capacitor is Connected to 100 V supply, what is the charge on each plate of the capacitor? (Given varepsilon_0=8.5xx10^-12C^2N^-1m^-2)