A compound microscope has an objective with `f_0 = 1.0 cm` and an eyepiece with focal length `f_e = 2.0 cm` and a tube having length of 20 cm. Find the magnification.

A compound microscope with an objective of 1.0 cm focal length and an eye-piece of 2.0 cm focal length has a tube of lengh of 20 cm.Calculate the magnifying power of the microscope,if the final image is formed at the near point of the eye.

An astronomical refractive telescope has an objective of focal length 20 m and an eyepiece of focal length 2 cm.

A compound microscope consists of an objective lens of focal length 2.0 cm and an eyepiece of focal length 6.25 cm separated by a distance of 15 cm. How far from the objective should an object be placed in order to obtain the final image at the least distance of distinct vision (25 cm)? What is the magnifying power of the microscope in?

A compound microscope uses an objective lens of focal length 4 cm and eyepiece lens of focal length 10 cm. An object is placed at 6 cm from the objective lens. Calculate the magnifying power of the compound microscope. Also calculate the length of the microscope.

In a compound microscope, the objective and eye-piece have focal lengths of 0.95 cm and 5 cm respectively and are kept at a distance of 20 cm.The last image is formed at a distance of 25 cm from the eye-piece. Calculate the position of the object and the total magnification.

A person with a normal near point (25 cm) using a compound microscope with objective of focal length 8.0 mm and an eyepiece of focal length 2.5cm can bring an object placed at 9.0mm from the objective in sharp focus. What is the separation between the two lenses? Calculate the magnifying power of the microscope.