In a experiment with light of `lambda = 5893 overset(@)A`, we had d = 4.00 mm, D = 1.50 m. Deduce the maximum slit width so that fringes may not be obliterated.

In a Young's double slit experiment,two slits are 1.5 mm apart and a screen in placed at a distance 1.2 m from the plane of the slits .The slits are illuminated with light of wavelength 6,000 overset @A .Find the inimum distance from the central maximum for which the intensity is half of the maximum intensity.

In double-slit experiment using light of wavelength 600 nm, the angular width of a fringe formed on a distant screen is 0.1^@ . What is the spacing between the two slits?

In Young's double slit experiment the width of the fringes obtained with ith of wavelength 4,500 overset@A is 1.8 mm.If the distance between the two slits is 0.3 mm,find the distance of the screen from the slits.What will be the fringe width,if the enitre apparatus is immersed in water of refraction index 4//3 .

in a Youing's double slit experiment,bicromatic light of wavelengths 400 nm and 560 nm are used.The distance between the slits is 0.1 mm and the distance between the plane of the slits and screen is 1.0m. the minimum distance between two successive regions of complete darkness is

In Young's double slit experiment, the widths of two slits are in the ratio 1:4 . Find at the ratio of maximum and minimum intensity in the interfernce pattern obtained.

In Young's double slit experiment, the widths of two slits are in the ratio 1:4 . Find at the ratio of maximum and minimum intensity in the interfernce pattern obtained.

In a Young's double slit experiment, the slits are separated by 0.03 cm and the screen is placed 1.5 m away. The distance between the central fringe and the fourth bright fringe is 1 cm. Determine the wavelength of light used in the experiment.

In a Young's double slit experiment ,the distance between the slits and the screen is 1 m.If the distance between the slits is 5 mm,the fringe width is found to be 0.1 mm.Calculate the wavelength of the light used.