`[[1,-tan alpha],[tan alpha,1]][[1,tan alpha],[-tan alpha,1]]` equals to `[[a,-b],[-b,a]]` then`sec^2 alpha` =?

tanalpha.tan(60^@-alpha).tan(60^@+alpha)=tan3alpha

tan alpha + 2 tan 2alpha + 4 tan 4 alpha + 8 cot 8 alpha =

1/(tan3alpha-tanalpha)-1/(cot3alpha-cotalpha)=cot2alpha

(1+tan alpha tan beta)^2 + (tan alpha - tan beta)^2 =

int tan(x-alpha).tan(x+alpha).tan 2x dx is equal to

if (1+tan alpha )(1+tan4 alpha ) =2 where alpha in (0 , pi/16 ) then alpha equal to

If n=pi/(4alpha), then tan alpha tan 2alpha tan 3 alpha ... tan(2n-1)alpha is equal to (a) 1 (b) 1/2 (c) 2 (d) 1/3

If alpha+beta=pi/4 then (1+tan alpha)(1+tan beta)=

If tan alpha =m/(m+1) and tan beta =1/(2m+1) , then alpha+beta is equal to

If minor of three-one element (i.e.M_(31)) in the determinant [{:(,0,1,sec alpha),(,tan alpha,-sec alpha,tan alpha),(,1,0,1)]:} is 1 then find the value of alpha (0 le alpha le pi).