ammonium hydrosulphide is in equilibrium with NH3 and H2S gases if total pressure at equilibrium is 3 atm then the Kp is (dissociation takes place at room temperature) (A) 4, (B) 212, (C) 36, (D) 27

The Kp of the reaction is NH_4HS(s)⇌NH_3(g)+H_2S( g) . If the total pressure at equilibrium is 30 atm.

The Kp of the reaction is NH_4HS(s)⇌NH_3(g)+H_2S( g) . If the total pressure at equilibrium is 42 atm.

The volume percentage of Cl_2 at equilibrium in the dissociation of PCl_5 under a total pressure of 1.5atm is (Kp = 0.202) ,

Solid NH_(4)HS(s) (ammonium hydrogen sulphate) dissociates to give NH_(3)(g) and H_(2)S(g) and is allowed to attain equilibrium at 100^(@)C . If the value of K_(p) for its dissociation is found to be 0.34 , find the total pressure at equilibrium at 100^(@)C . If the value of K_(p) for its dissociation is found to be 0.34 , find the total pressure at equilibrium and partial pressure of each component.

For the equilibrium reaction NH_4Cl hArr NH_3(g)+HCl(g), K_P=81 "atm"^2 .The total pressure at equilibrium is 'X' times the pressure of NH_3 .The value of X will be

For PCl_5(g)⇌PCl_3(g)+Cl_2(g) at equilibrium, K_p = P/3 , where P is equilibrium pressure. Then degree of dissociation of PCl_5 at that temperature is ?

In the reaction AB(g) hArr A(g) + B(g) at 30^(@)C, k_(p) for the dissociation equilibrium is 2.56xx10^(-2) atm . If the total pressure at equilibrium is 1 atm, then the percentage dissociation of AB is

K_p for the equation A(s)⇋ B(g) + C(g) + D(s) is 9 atm^2 . Then the total pressure at equilibrium will be

An amount of solid NH_4 HS is placed in a flask already containing ammonia gas at a certain temperature and 0.50 atm pressure . Ammonium hydrogen sulphide decomposses to yield NH_3 and H_2S gases in the flask. When the decomposition reaction reaches equilibrium , the total pressure in the flask rises to 0.84 atm. The equilibrium constant for NH_4HS decomposition at this temperature is

Solid Ammonium carbamate dissociates as: NH_(2)COONH_(4)(s)hArr2NH_(3)(g)+CO_(2)(g). In a closed vessel, solid ammonium carbonate is in equilibrium with its dissociation products. At equilibrium, ammonia is added such that the partial pressure of NH_(3) at new equilibrium now equals the original total pressure. Calculate the ratio of total pressure at new equilibrium to that of original total pressure. Also find the partial pressure of ammonia gas added.