If `A^(T)=A` and `B^(T)=B` then

Consider three square matrices A, B and C of order 3 such that A^(T)=A-2B and B^(T)=B-4C , then the incorrect option is

If A is a nonsingular matrix such that A A^(T)=A^(T)A and B=A^(-1) A^(T) , then matrix B is

If A is an 3xx3 non-singular matrix such that A A^T=A^TA and B=A^(-1)A^T," then " B B^T equals

If A is a non-singular matrix such that AA^(T)=A^(T)A and B=A^(-1)A^(T), the matrix B is a.involuntary b.orthogonal c.idempotent d. none of these

If A^(T), B^(T) are transpose of the square matrices A, B respectively, then (AB)^(T)=

If A is a 3 xx 3 non-singular matrix such that A A^(T) = A^(T)A " and "B = A^(-1)A^(T), " then "B B^(T) is equal to

Two particles, A and B, are in motion in the xy-plane. Their co-ordinates at each instant of time t (t ge 0) are given by x_(A) =t, y _(A)=2t , x _(B)=1-t and y _(B) =t. The minimum distance between particles A and B is :

If A={:[(2,3,5,6),(-1,2,-3,4)]:}andB={:[(4,-5,3,7),(8,-3,-1,2)]:} , then find A^(T)+B^(T)and(A+B)^(T) . What do you notice ?