A body released from certain height reaches the surface of the earth after t seconds. if the body is released from the same height on the moon , it reaches the surface after ( gm = ge/6)

A body released from a great height and falls freely towards the earth. Another body is released from the same height exactly one second later. Then the separation between the two bodies, two seconds after the release of the second body is

A body is released from a great height and falls freely towards the earth. Exactly one sec later another body is released. What is the distance between the two bodies 2 sec after the release of the second body ?

A body at rest starts from a point at a distance r (gtR) from the centre of the Earth. If M and R stand for the speed of the body when it reaches the Earth surface is

A stone drop from height h reaches to earth surface in 1 sec. if the same stone taken to moon and drop freely then it will reaches from the surface of the moon in the time (the 'g' of moon is 1/6 times of earth)-

A body falls freely from a height 'h' its average velocity when it reaches earth is

A particle is launched from a height 8R above the surface of earth and it is given a speed ((GM)/(8R)) parallel to the surfaces then

If mass of a body is M on the earth surface, then the mass of the same body on the moon surface is

A ring,solid sphere and a disc are rolling down from the top of the same height, then the sequence to reach on the surface is

A body released from the top of a tower of height h takes T seconds to reach the ground. The position of the body at T/4 seconds is

A body is released form the top of a tower of height h meters. It takes t seconds to reach the ground. Where is the ball at the time t/2 sec ?