`N` divisions on the main scale of a vernier callipers coincides with `(N+1)` divisions of the vernier scale. If each division of main scale is `a` units, Then the least count of the instrument is

N divisions on the main scale of a vernier callipers coincide with (N + 1) divisions on the vernier scale. If each division on the main scale is 'a' units, then the least count of the instrument is

19 divisions on the main scale of a vernier calipers coincide with 20 divisions on the vernier scale. If each division on the main scale is of 1 cm , determine the least count of instrument.

In vernier callipers, m divisions of main scale with (m + 1) divisions of vernier scale. If each division of main scale is d units, the least count of the instrument is

in an experiment the angles are required to be using an instrument, 29 divisions of the main scale exactly coincide with the 30 divisions of the vernier scale. If the sallest division of the main scale is half- a degree (= 0.5^(@) , then the least count of the instrument is :

1 cm on the main scale of a vernier callipers is divided into 10 equal parts. If 10 divisions of vernier coincide with 8 small divisions of main scale, then the least count of the calliper is.

1 cm on the main scale of a vernier calipers is divided into 10 equal parts. If 10 divisions of vernier coincide with 8 small divisions of main scale, then the least count of the caliper is.

In a vernier calliper, N divisions of vernier scale coincide with (N-1) divisions of main scale (in which division represent 1mm). The least count of the instrument in cm. should be

If n^(th) division of main scale coincides with (n + 1)^(th) divisions of vernier scale. Given one main scale division is equal to 'a' units. Find the least count of the vernier.

One centimetre on the main scale of vernier callipers is divided into ten equal parts. If 20 divisions of vernier scale coincide with 19 small divisions of the main scale then what will be the least count of the callipers.

Circular scale of a screw gauge moves through 4 divisions of main scale in one rotation. If the number of divisions on the circular scale is 200 and each division of the main scale is 1 mm., the least count of the screw gauge is