`3mg` ` CaCO_3` is present in `100 L` aqueous solution, then what will be its ppm concentration?
1)3ppm
2)0.03ppm
3)30ppm
4)40ppm

14.2 g Na_2SO_4 is present in 10^2 kg water. Its concentration in ppm is

20 mg of K^(o+) ions are present in 1 L of aqueous solution. Density of the solution is 0.8 mL^(-1) . What is the concentration of K^(o+) ions in ppm?

How much Ca(NO_(3))_(2) in mg must be present in 50 ml of a solution with 2.35 ppm of Ca?

Calculate molarity of CaCO_(3) (aq.) solution which has concentration of CaCO_(3)=200 ppm.

What is meant by 5 ppm CaCO_(3) solution?

A concentration of 1 ppm means that

What is molarity of K^(+) in aqueous solution that contains 17.4 ppm of K_(2)SO_(4)(174g"mol"^(-1)) ?

5 litre of a solution contains 25 mg of CaCO_(3) . What is its concentration in ppm? (mol.wt of CaCO_(3) is 100)

A water is said to be soft water if it produces sufficient foam with the soap and water that does not produce foam with soap is known as hard water. Hardness has been classified into two types (i)Temporary hardness (ii) Permanent hardness. Temporary hardness is due to presence of calcium and magnesium bicarbonate. It is simply removed by boiling as Ca(HCO_(3))_(2)overset(Delta)rarr CaCO_(3)darr+CO_(2)uarr+H_(2)O Mg(HCO_(3))_(2)overset(Delta)rarr MgCO_(3)darr+CO_(2)uarr+H_(2)O temporary hardness can also be removed by addition of slaked lime, Ca(OH)_(2) Ca(HCO_(3))_(2)+Ca(OH)_(2)to2CaCO_(3)darr+2H_(2)O permanent hardsness is due to presencce of sulphates and chlorides of Ca,Mg,etc. It is removed by washing soda as CaCl_(2)+Na_(2)CO_(3)toCaCO_(3)darr+2NaCl CaSO(4)+Na_(2)CO_(3)to CaCO_(3)darr+Na_(2)SO_(4) Permanent hardness also removed by ion exchange resin process as 2RH+Ca^(2+) to R_(2)Ca+2H^(+) 2ROH+SO_(4)^(2-)toR_(2)SO_(4)+2OH^(-) The degree of hardness of water is measured in terms of PPm of CaCO_(3) 100 PPm means 100 g of CaCO_(3) is present in 10^(6) g of H_(2)O . If any other water sample which contain 120 PPm of MgSO_(4) , hardness in terms of CaCO_(3) is equal to =100 PPm. What is the mass of Ca(OH)_(2) required for 10 litre of water remove temporary hardness of 100 PPm due to Ca(HCO_(3))_(2) ?

A water is said to be soft water if it produces sufficient foam with the soap and waterthat does not produce foam with soap is known as hard water. Hardness has been classified into two types (i)Temporary hardness (ii) Permanent hardness. Temporary hardness is due to presence of calcium and magnesium bicarbonate. It is simply removed by boiling as Ca(HCO_(3))_(2)overset(Delta)rarr CaCO_(3)darr+CO_(2)uarr+H_(2)O Mg(HCO_(3))_(2)overset(Delta)rarr MgCO_(3)darr+CO_(2)uarr+H_(2)O temporary hardness can also be removed by addition of slaked lime, Ca(OH)_(2) Ca(HCO_(3))_(2)+Ca(OH)_(2)to2CaCO_(3)darr+2H_(2)O permanent hardsness is due to presencce of sulphates and chlorides of Ca,Mg,etc. It is removed by washing soda as CaCl_(2)+Na_(2)CO_(3)toCaCO_(3)darr+2NaCl CaSO(4)+Na_(2)CO_(3)to CaCO_(3)darr+Na_(2)SO_(4) Permanent hardness also removed by ion exchange resin process as 2RH+Ca^(2+)toR_(2)Ca+2H^(+) 2ROH+SO_(4)^(2-)toR_(2)SO_(4)+2OH^(-) The degree of hardness of water is measured in terms of PPm of CaCO_(3) 100 PPm means 100 g of CaCO_(3) is present in 10^(6) g of H_(2)O . If any other water sample which contain 120 PPm of MgSO_(4) , hardness in terms of CaCO_(3) is equal to =100 PPm. A 200 g sample of hard water is passed through the column of cation exchange resin, in which H^(+) is exchanged by Ca^(2+) .The outlet water of column required 50mL of 0.1 M NaOH for complete neutralization.What is the hardness of Ca^(2+) ion in PPm?