If `(x^(2))/(x-2)>0,` then `x in`

If (|x-2|)/(x-2)geq0, then x in [2,oo) b. x in (2,oo) c. x in (-oo,2) d. x in (-oo,2]

If |x^(2)|-3|x|+2=0 then x =

y = cos ^(-1)((1 - x^(2))/(1+ x^(2))) 0 lt x lt 1

y = sin ^(-1)((1 - x^(2))/(1+ x^(2))) 0 lt x lt 1 find dy/dx

Draw the graph of y=x^(2)+(1)/(x^(2)), x !=0 .

The equation 2 "cos"^(2)((x)/(2))"sin"^(2) x = x^(2) + (1)/(x^(2)), 0 le x le (pi)/(2) has

The equation 2 "cos"^(2)((x)/(2))"sin"^(2) x = x^(2) + (1)/(x^(2)), 0 le x le (pi)/(2) has

The number of solutions of 2"cos"^(2)((x)/(2))"sin"^(2) x =x^(2) + (1)/(x^(2)), 0 le x le (pi)/(2), is

Given the function f(x)=x^2e^-(2x) ,x>0. Then f(x) has the maximum value equal to a) e^-1 b) (2e)^-1 . c) e^-2 d) none of these

Solve : ((x)/(x+2))^(2)-7((x)/(x+2))+12=0, x ne -2 .