Solve :
( a ) `( sqrt(3) - sqrt(2 ) )^2`
( b ) `( b - b )^2`

(a + sqrt b)(a-sqrt b) = a^2 - b

If a = (sqrt(3) + sqrt(2))/(sqrt(3) - sqrt(2)) and b = (sqrt(3) - sqrt(2))/(sqrt(3) + sqrt(2)) , then value of a^(2) + b^(2) is

(1+sqrt(2))/(3-2sqrt(2))=A sqrt(2)+B

x = ( sqrt ( a + b ) - sqrt (a -b ))/( sqrt (a +b ) + sqrt (a -b )), then what is bx ^(2) - 2ax + b equal to (b ne 0) ?

If a = (sqrt(3) - sqrt(2))/(sqrt(3) + sqrt(2)) and b = (sqrt(3) + sqrt(2))/(sqrt(3) - sqrt(2)) then value of sqrt(3a^2 - 5ab + 3b^2) is

find a and b (6)/(sqrt(3)-sqrt(2))=a sqrt(3)-b sqrt(2)

Find the value of a and b . (sqrt11 - sqrt7 ) / (sqrt 11 + sqrt 7) = a - b sqrt 77 (i) a = 9/2 , b = 1/2 (ii) a = 2/9, b = 2/3 (iii) a = 2/5, b = 1/2 (iv) a = 9/2, b =5/2