What is produced at anode on electrolysis of aq. `CuSO_4` using copper electrodes?
`Cu^(2+)`
`H_2`
`O_2`
`S_(2)O_(8)^(2-)`

State the reason for difference in product formed at the anode during electrolysis of aq. CuSO_(4) soln. using i] active electrodes ii] inert electrode-platinum anode.

Select the correct answer from the list given in brackets : The ion which is discharged at the anode during the electrolysis of copper sulphate solutions using copper electrodes as anode and cathode. [Cu^(2+) , OH^(-) SO_(4)^(2-) , H^(+)]

What do you understand by electrolysis ? What chemical processes occur during the electrolysis of aqueous solution of: (i) CuSO_(4) using platinum electrodes? (ii) CuSO_(4) using copper electrodes?

In the electrolysis of CuSO_4 , the reaction: Cu^(2+)+2e^(-) rarr Cu ,takes place at:

The ion which is discharged at the anode during the electrolysis of copper sulphate solution using platinum electrode as anode and cathode [Cu^(2+) OH^(-),SO_(4)^(2-) H^(+)]

During electrolysis, O_(2)(g) is evolved at anode in

During electrolysis, O_(2)(g) is evolved at anode in

During electrolysis of an aqueous solution of CuSO_(4) using copper electrodes, if 2.5g of Cu is deposited at cathode, then at anode

Assertion: During electrolysis of CuSO_4 (aq) using copper electrodes, copper is dissolved at anode and deposited at cathode. Reason: Oxidation takes place at anode and reduction at cathode.

Electrolysis of aqueous HF produces O_2 at anode but not F_2 Explain.