ln `Delta ABC`, `tan A=3`,`tan B=(2)/(3)` `c=sqrt(10)` then circum radius of `Delta` is
(1) `11sqrt((13)/(10))`
(2) `(10sqrt(13))/(11)`
(3) `(sqrt(130))/(11)`
(4) `(5sqrt(13))/(11)`

If Delta ABC , if tan A + tan B + tan C = 3sqrt(3) , then the triangle is :

Let y=1/(2+1/(3+1/(2+1/(3+)))) , then the value of y is (a) (sqrt(13)+3)/2 (b) (sqrt(13)-3)/2 (c) (sqrt(15)+3)/2 (d) (sqrt(15)-3)/2

if cos^(-1)((2)/(3x))+cos^(-1)((3)/(4x))=(pi)/2, x>3/4 then x= (a) (sqrt(145))/(11) (b) (sqrt(145))/(12) (c) (sqrt(146))/(10) (d) (sqrt(146))/(11)

Two circles, each having radius 4, have a common tangent given by 3x+2y-6=0 at (2, 0) . Then their centres are : (A) (2+ 5/sqrt(13), 8/sqrt(13)), (2- 5/sqrt(13) , (-8)/sqrt(13)) (B) (2+ 12/sqrt(13), 8/sqrt(13)) , (2- 12/sqrt(13), (-8)/sqrt(13)) (C) (2, 3), (4, 5) (D) none of these

The incenter of the triangle with vertices (1,sqrt(3)),(0,0), and (2,0) is (a) (1,(sqrt(3))/2) (b) (2/3,1/(sqrt(3))) (c) (2/3,(sqrt(3))/2) (d) (1,1/(sqrt(3)))

The value of |{:(sqrt(13 )+ sqrt(3), 2sqrt(5),sqrt(5)),(sqrt(15) + sqrt(26),5,sqrt(10)),(3 + sqrt(65), sqrt(15),5):}|

The maximum value of Delta=|(1,1,1),(1,1+sintheta,1),(1+costheta,1,1)| is ( theta is real) (A) 1/2 (B) (sqrt(3))/2 (C) sqrt(2) (D) -(sqrt(3))/2

The value of root(3)(5+2sqrt(13)) + root(3)(5-2sqrt(13)) is= ……………..

Rationalise the denominator in each of the following: (i) 2/(sqrt(7)) (ii) 2/(3sqrt(3)) (iii) (2sqrt(7))/(sqrt(11))

Simplify : (i) (sqrt(5)+sqrt(2))^2 (ii) (sqrt(11)-sqrt(5))^2