Identify the odd one :

Options

A. Methane
B. HCI
C. NaCI
D. Nitrogen

Explanation

To identify the odd one out from the given molecules: methane (CH₄), hydrochloric acid (HCl), sodium chloride (NaCl), and nitrogen (N₂), we will analyze the type of bonding in each molecule.

### Step-by-Step Solution:

1. **Identify the Molecules**: The four molecules are:
- Methane (CH₄)
- Hydrochloric acid (HCl)
- Sodium chloride (NaCl)
- Nitrogen (N₂)

2. **Analyze Methane (CH₄)**:
- Methane consists of one carbon atom and four hydrogen atoms.
- The carbon atom shares its four valence electrons with four hydrogen atoms.
- This results in the formation of covalent bonds.
- **Conclusion**: Methane has covalent bonding.

3. **Analyze Hydrochloric Acid (HCl)**:
- Hydrochloric acid consists of one hydrogen atom and one chlorine atom.
- The chlorine atom has seven valence electrons and shares one electron with hydrogen.
- This results in the formation of a covalent bond.
- **Conclusion**: HCl has covalent bonding.

4. **Analyze Sodium Chloride (NaCl)**:
- Sodium chloride consists of one sodium atom and one chlorine atom.
- Sodium has one electron in its outer shell, while chlorine has seven.
- Sodium donates its one electron to chlorine, resulting in the formation of Na⁺ and Cl⁻ ions.
- The bond formed is ionic due to the transfer of electrons.
- **Conclusion**: NaCl has ionic bonding.

5. **Analyze Nitrogen (N₂)**:
- Nitrogen consists of two nitrogen atoms.
- Each nitrogen atom has five valence electrons and shares three electrons with the other nitrogen atom.
- This results in the formation of a triple covalent bond.
- **Conclusion**: Nitrogen has covalent bonding.

6. **Identify the Odd One**:
- From the analysis:
- Methane (CH₄) - Covalent bond
- Hydrochloric acid (HCl) - Covalent bond
- Sodium chloride (NaCl) - Ionic bond
- Nitrogen (N₂) - Covalent bond
- The odd one out is **Sodium Chloride (NaCl)** because it has ionic bonding, while the others have covalent bonding.

### Final Answer:
The odd one is **Sodium Chloride (NaCl)**.