A `4 mu F` capacitor is charged to `80V` and another capacitor of `6 mu F` capacity is charged to `30V` .When they are connected the energy lost by `4 mu F` capacitor is `Km J` ,the value of `K` is

A capacitor of capacitance 4muF is charged to 80V and another capacitor of capacitance 6muF is charged to 30V are connected to each other using zero resistance wires such that the positive plate of one capacitor is connected to the positive plate of the other. The energy lost by the 4muF capacitor in the process in X**10^(-4)J . Find the value of X.

A capacitor of capacitance 4muF is charged to 80V and another capacitor of capacitance 6muF is charged to 30V are connected to each other using zero resistance wires such that the positive plate of one capacitor is connected to the positive plate of the other. The energy lost by the 4muF capacitor in the process in X**10^(-4)J . Find the value of X.

A capacitor A of capacitance 4muF is charged to 30V and another capacitor B of capacitance 2muF is charged to 15V . Now, the positive plate of A is connected to the negative plate of B and negative plate of A to the positive plate of B . find the final charge of each capacitor and loss of electrostatic energy in the process.

In the given circuit, the charge on 4 mu F capacitor will be :

In the given circuit, the charge on 4 mu F capacitor will be : .

In the circuit shown , charge on the 5 mu F capacitor is :

A capacitor 4 muF charged to 50 V is connected to another capacitor of 2 muF charged to 100 V with plates of like charges connected together. The total energy before and after connection in multiples of (10^(-2) J) is

A capacitor of capacitance 6 mu F is connected with an emf sourface 3 V. Electrostaci energy stored in the capacitor is

In the given arrangement of the capacitors, one 3mu F capacitor has got 600 mu J of energy. Then the potential difference across 2 mu F capacitor is

Calculate energy stored in a capacitor of 5 mu F when it is charged to a potential of 250 volt.