n arithmetic means are inserted between 3 and 17 such that ratio of first and the last means is 1: 3, find n.

Insert 6 arithmetic means between 3 and 24.

There are n arithmetic means between 3 and 17. The ratio of the last mean to the first mean is 3: 1. Find the value of n.

Insert 10 arithmetic means between 2 and 57.

Insert 5 arithmetic means between 8 and 26.

The sum of two numbers is 13/6 . An even number of arithmetic means are inserted between them and their sum exceeds their number by 1. Find the number of means inserted.

There are n AM's between 3 and 54.Such that the 8th mean and (n-2) th mean is 3 ratio 5. Find n.

Between 1 and 31, n A.M's have been inserted in sucha a way that the ratio of 7th and (m-1)th means is 5:9, find the value of m.

Insert 6 harmonic means between 3 and (6)/(23)

If nine arithmetic means and nine harmonic means are inserted between 2 and 3 alternatively, then prove that A+6//H=5 (where A is any of the A.M.'s and H the corresponding H.M.) dot

Suppose x and y are two real numbers such that the rth mean between x and 2y is equal to the rth mean between 2x and y when n arithmatic means are inserted between them in both the cases. Show that : (n+1)/r-y/x=1 .