Sum the series `7+(-1)+1/7-(1/(49))+……`to`infty.`

The sum of the series is 1+4/5+7/5^2+10/5^3+…………infty is:

Sum of the series sum_(r=1)^(n) (r^(2)+1)r! is

Find the sum of n terms \ of the series: 1/(1. 2)+1/(2. 3)+1/(3. 4)+dot+ 1/n dot((n+1))

Add: 1/7 + 1/7

Simplify 7^(1/5)/7^(1/3)

If the sum to n terms of the series (1)/(1*3*5*7)+(1)/(3*5*7*9)+(1)/(5*7*9*11)+"......" is (1)/(90)-(lambda)/(f(n)) , then find f(0), f(1) and f(lambda)

The sum to n terms of the series (1)/(2) + (3)/(4) + (7)/(8) + (15)/(16)+…. is equal to :

The sum of the series: 1+(1)/(3)+(1.3)/(3.6)+(1.3.5)/(3.6.9)+(1.3.5.7)/(3.6.9.12+ ---- is

The rth term of the series 2(1/2)+1(7/13)+1(1/9)+20/23+..... is

Sum up the following series :- 7 + 12+ 17 + ……+77.