The co-ordinates of A,B,C and D are respectivley (6,3),(-3,5),(4,-2) and (x,3x) and `(Area of triangleDBC)/(area of triangleABC) = 1/2`, find x.

The coordinates of points A,B,C and D are (-3, 5), (4, -2), (x, 3x) and (6, 3) respectively and Area of (Delta ABC)/(Delta BCD)=(2)/(3) ,find x.

Consider A(2,3,4),B(4,3,2) and C(5,2,-1) be any three points. Find the area of triangle ABC.

If the points A(x_1,y_1), B(x_2,y_2) and C(x_3,y_3) are collinear, then area of triangle ABC is:

Let A(1, 2, 3), B(0, 0, 1) and C(-1, 1, 1) are the vertices of triangleABC . Q. The area of (triangleABC) is equal to

The coordinates of A ,\ B ,\ C are (6,\ 3),\ (-3,\ 5) and (4,\ -2) respectively and P is any point (x ,\ y) . Show that the ratio of the areas of triangles P B C and A B C is |(x+y-2)/7| .

If A(x_1,y_1),B(x_2,y_2),C(x_3,y_3) are the vertices of the triangle then find area of triangle

Find 'x' such that the four points : A(3,2,1),B(4,x,5),C(4,2,-2) and D(6,5,-1) are coplanar.

Let A(4, 2), B (6, 5) and C (1, 4) be the vertices of triangleABC . :- If (x_1,y_1) , B (x_2,y_2) and C (x_3,y_3) the vertices of triangleABC , find the coordinates of the centroid of the triangle.