The equations of the sides AB,BC,CA of a triangle ABC are 3x + 4y = 6, 12 x - 5y = 3 and 4x - 3y + 12= 0. Find the equation of the internal bisector of angle A.

If the equations of three sides of a triangle are x+y=1, 3x + 5y = 2 and x - y = 0 then the orthocentre of the triangle lies on the line/lines

Find the equations of the sides of the triangle having (3, - 1) as a vertex, x - 4y + 10 = 0 and 6x + 10y - 59 = 0 being the equations of an angle bisector and a median respectively drawn from different vertices.

The three sides AB, BC, CA of a triangle are 5x - 3y +2 = 0,x-3y-2=0 and x+y-6=0 respectively. Find equation of the altitude through the vertex A.

The equations of two sides of a triangle are 3x-2y+6=0\ a n d\ 4x+5y-20\ a n d\ the orthocentre is (1,1). Find the equation of the third side.

In a triangle ABC , if the equation of sides AB,BC and CA are 2x- y + 4 = 0 , x - 2y - 1 = 0 and x + 3y - 3 = 0 respectively ,Tangent of internal angle A is equal to

Find the equations of the bisectors of the angles formed by the lines : 3x- 4y + 12 = 0 and 4x + 3y + 2=0.

For the triangle ABC whose vertices are A (-2, 3), B (4, - 3) and C (6, 5), find the equation of : the perpendicular bisector of the side BC.

Equation of the base of an equilateral triangle is 3x + 4y = 9 and its vertex is at point (1,2) .Find the equations of the other sides and the length of each side of the triangle .

The sides of a triangle are 3x + 4y, 4x + 3y and 5x+5y units, where x gt 0, y gt 0 . The triangle is

Find the equations of the bisectors of the internal angles of the triangle whose sides are : 3x + 4y -6 = 0, 12x -5y-3 = 0, 4x - 3y + 12 =0 .