The centre of a circle is (3,4) and a point on the circle is (6,-2). Find the co-ordinates of the other end of the diameter through this point.

If (4, 1) be an end of a diameter of the circle x^2 + y^2 - 2x + 6y-15=0 , find the coordinates of the other end of the diameter.

Find the equation of the circle, the co-ordinates of the end points of whose diameter are (3, 4) and (- 3, - 4).

Write the co-ordinates of the centre of the circle : 2x^2 + 2y^2-6x+8y-4=0 .

The co-ordinates of a point are (1, -2, 7). Find the co-ordinates of the seven points whose absolute values are the same as those of the co-ordinates of the given point.

If a circle, whose centre is (-1,1) touches the straight line x+2y = 12, then the co-ordinates of the point of contact are

Find the equation of a circle with centre (2,2) and passes through the point (4,5).