Find the equation of the parabola whose vertex is at (0,4) and focus is at (0,2).

Find the equation of the parabola with vertex at (0, 0) and focus is at (0, 2).

Derive the equation of the parabola with its vertex at (3,2) and its focus at (5,2) .

Find the equation of the parabola with vertex is (2, 1) and the directrix is x = y -1.

Find the equation of the parabola whose focus is (4,-3) and vertex is (4,-1).

Find the equation of the parabola, which has vertex (0, 0) and is symmetric about y-axis and passes through the point (2, - 3).

Find the equation of the parabola whose focus is (5,3) and directrix is the line 3x-4y+1=0.

Find the equation of the parabola whose focus is at (-1,-2) and the directrix the line x-2y+3=0

Prove that the equation of the parabola whose vertex and focus are on the X-axis at a distance a and a'from the origin respectively is y^2=4(a'-a)(x-a)

Find the focus of the parabola x^2=4y

Find the equation of the parabola with vertex at the origin and satisfying the condition : Focus (2, 0) , Directrix x = -2 .