What is the vertex of te parabola `y^2 = -4x`?

The vertex of the parabola y^2=4a(x+a) is:

If (a , b) is the midpoint of a chord passing through the vertex of the parabola y^2=4x , then (a) a=2b (b) a^2=2b (c) a^2=2b (d) 2a=b^2

Tangent is drawn at any point (x_1, y_1) other than the vertex on the parabola y^2=4a x . If tangents are drawn from any point on this tangent to the circle x^2+y^2=a^2 such that all the chords of contact pass through a fixed point (x_2,y_2), then

The vertex of the parabola y^2+6x-2y+13=0 is

If the vertex of the parabola y=x^(2) -8x+c lies on x-axis, then the value of c, is

Find the area of the triangle formed by the lines joining the vertex of the parabola x^2 = 12y to the ends of its latus rectum.

A parabola (P) touches the conic x^2+xy+y^2-2x-2y+1=0 at the points when it is cut by the line x+y+1=0. If (a,b) is the vertex of the parabola (P), then the value of |a-b| is

An equilateral triangle is inscribed in the parabola y^(2)=4ax whose vertex is at the vertex of the parabola .Find the length of its side.