Find the focus of the parabola
`x^2=4y`

What is the focus of the parabola x^2+y^2+2xy−6x−2y+3=0 .

The focus of the parabola y^2= 4ax is :

A parabola is drawn with focus at (3,4) and vertex at the focus of the parabola y^2-12x-4y+4=0 . The equation of the parabola is

Radius of the largest circle which passes through the focus of the parabola y^2=4x and contained in it, is

Find the focus, vertex, equation of the directrix and the axis of the parabola x = y^2- 2y + 3 .

The focus of the parabola x^2-8x+2y+7=0 is

The coordinates of the focus of the parabola described parametrically by x =5t^2+2,y=10t+4 are :

Find the locus of the middle points of the chords of the parabola y^2=4a x which subtend a right angle at the vertex of the parabola.

If the distances of two points P and Q from the focus of a parabola y^2=4x are 4 and 9,respectively, then the distance of the point of intersection of tangents at P and Q from the focus is