Write down the equation of the tangent to the vertex of the parabola `x^2 = -4y`.

The vertex of the parabola y^2=4a(x+a) is:

The vertex of the parabola y^2+6x-2y+13=0 is

Find the focus of the parabola x^2=4y

The equation of tangent in slope form to the the parabola y^2 = 4x is

The equation of the latus retum of the parabola x^(2)+4x+2y=0 is

Find the area of the triangle formed by the lines joining the vertex of the parabola x^2 = 12y to the ends of its latus rectum.

Find the area of the triangle formed by the lines joining the vertex of the parabola x^2= 12y to the ends of its latus-rectum.