Find the eccentricity of the hyperbola `9y^2 - 4x^2 = 36`.

The eccentricity of the hyperbola 4x^(2)-9y^(2)=36 is :

In the following, find the coordinates of the foci and the vertices, the eccentricity and the length of the latus rectum of the hyperbolas. 9y^2 - 4x^2 = 36

Find the lengths of transverse and conjugate axes, co-ordinates of foci, vertices and the eccentricity for the following hyperbola : 2x^2 -3y^2 -6= 0 .

If e and e_(1) , are the eccentricities of the hyperbolas xy=c^(2) and x^(2)-y^(2)=c^(2) , then e^(2)+e_(1)^(2) is equal to

Find the co-ordinates of the vertices, the foci, the eccentricity and the length of latus-rectum of the hyperbola : 9y^2-4x^2 =36 .

Find the lengths of transverse and conjugate axes, co-ordinates of foci, vertices and the eccentricity for the following hyperbola : 16x^2 -9y^2 =144 .

If e_1 is eccentricity of the ellipse x^2/16+y^2/7=1 and e_2 is eccentricity of the hyperbola x^2/9-y^2/7=1 , then e_1+e_2 is equal to:

sqrt 2009/3 (x^2-y^2)=1 , then eccentricity of the hyperbola is :

Find the lengths of transverse and conjugate axes, co-ordinates of foci, vertices and the eccentricity for the following hyperbola : 3x^2 -2y^2=1 .

lf the eccentricity of the hyperbola x^2-y^2(sec)^2alpha=5 is sqrt3 times the eccentricity of the ellipse x^2(sec)^2alpha+y^2=25, then a value of alpha is : (a) pi/6 (b) pi/4 (c) pi/3 (d) pi/2