What is the centre of the ellipse `(x^2)/4 + (y^2)/9 = 1`.

The maximum distance of the centre of the ellipse (x^(2))/(16) +(y^(2))/(9) =1 from the chord of contact of mutually perpendicular tangents of the ellipse is

C is the centre of the ellipse x^(2)/16+y^(2)/9=1 and A and B are two points on the ellipse such that /_ACB=90^@ , then 1/(CA)^(2)+1/((CB)^(2))=

If e and e' are the eccentricities of the ellipse 5x^(2) + 9 y^(2) = 45 and the hyperbola 5x^(2) - 4y^(2) = 45 respectively , then ee' is equal to

Find the area of the region bounded by the ellipse (x^(2))/4+(y^(2))/9 = 1

Find the equation of the tangent to the ellipse (x^2)/a^2+(y^2)/(b^2) = 1 at (x_1y_1)

The distance between the directrices of the ellipse x^2/4+y^2/9=1 is:

the centre of the ellipse ((x+y-2)^(2))/(9)+((x-y)^(2))/(16)=1 , is

The eccentricity of the ellipse 4x^2 + 9y^2 = 36 is :

Find the area of region bounded by the ellipse x^2/4 + y^2/9 = 1

Let d be the perpendicular distance from the centre of the ellipse x^2/a^2+y^2/b^2=1 to the tangent drawn at a point P on the ellipse. If F_1 & F_2 are the two foci of the ellipse, then show the (PF_1-PF_2)^2=4a^2(1-b^2/d^2) .