Find the point(s) on the parabola `y^2 =8x` whose focal distance is 4.

Find the focus of the parabola x^2=4y

Let P be the point on the parabola, y^(2)=8x which is at a minimum distance from the center C of the circle , x^(2)+(y+6)^(2)=1 . Then the equation of the circle, passing through C and having its canter at P is

For the parabola y^2 = 4x , the point P whose focal distance is 17, is :

Find a point on the parabola y = (x-2)^2 , where the tangent is parallel to the chord joining (2,4) and (4,4)

Find a point on the parabola y =(x-3)^2 , where the tangent is parallel to the line joining (3,0) and (4,1).

The eccentricity of the parabola y^2 =-8x is :

Find a point on the parabola y = (x-3)^2 , where the tangent s parallel to the chord joining (3,0) and (4,1)

Let P be the point on the parabola y^(2)4x which is at the shortest distance from the center S of the circle x^(2)+y^(2)-4x-16y+64=0 . Let Q be the point on the circle dividing the line segment SP internally. Then

Find the equation of the parabola whose focus is at (-1,-2) and the directrix the line x-2y+3=0

Find the equation of the parabola whose focus is the point (- 1,- 2) and directrix is x -2y+3 =0.