True or False:
The line x + 3y = 0 is a diameter of the circles `x^2 + y^2 + 6x + 2y = 0`.

The equation of one of the diameters of the circle x^2+y^2 - 6x + 2y =0 is:

The radius of the circle, having centre at (2, 1) , whose one of the chord is a diameter of the circle x^2 + y^2-2x-6y + 6 = 0

If the line x+2b y+7=0 is a diameter of the circle x^2+y^2-6x+2y=0 , then find the value of b .

Statement I The line 3x-4y=7 is a diameter of the circle x^(2)+y^(2)-2x+2y-47=0 Statement II Normal of a circle always pass through centre of circle

The centre of the circle x^(2)+y^(2)-6x+4y-1=0 is

True or false The line x=y=z lies in the plane x-2y+z-1=0.

One of the diameters of the circle x^2+y^2-12x+4y+6=0 is given by

The line 4y - 3x + lambda =0 touches the circle x^2 + y^2 - 4x - 8y - 5 = 0 then lambda=

Find the equation of the circle passing through the point of intersection of the circles x^2 + y^2 - 6x + 2y + 4 = 0, x^2 + y^2 + 2x - 4y -6 = 0 and with its centre on the line y = x.

The line 3x -4y = k will cut the circle x^(2) + y^(2) -4x -8y -5 = 0 at distinct points if