The centre of the circle `x^2 + y^2 - 2ax = 0,(ane0)` is at the point

A

(0,0)

B

(0,a)

C

(a,0)

D

none of these

Verified by Experts

Similar Questions

Explore conceptually related problems

The centre of the circle x^2+y^2+8x+10y-8=0 is:

The centre of the circle x^(2)+y^(2)-6x+4y-1=0 is

Find the equation of tangent to the circle x^(2)+y^(2)-2ax=0 at the point [a(1+cosalpha),asinalpha]

Find the equation of a circle passing through the centre of the circle x^2 + y^2+ 8x +10y-7=0 and concentric with the circle 2x^2 + 2y^2-8x-12y-9=0 .

If the circle x^2+y^2 +4x+22y + c = 0 bisects the circumference of the circle x^2 + y^2-2x + 8y-d = 0 ,then (c+d) is equal to

Equation of circle passing through the centre of the circle x^2+y^2-4x-6y-8=0 and being concentric with the circle x^2+y^2-2x-8y-5=0 is

The point of tangency of the circles x^2+ y^2 - 2x-4y = 0 and x^2 + y^2-8y -4 = 0 , is

Find the centre and radius of the circle : 2x^2 + 2y^2- x=0 .

In the following, find the centre and radius of the circles.:- x^2 + y^2 -8x + 10y - 12 = 0

Find the centre and radius of the circle : x^2 + y^2- 8x+ 10y- 12 = 0 .