Let A(2,2,-3) ,B(5,6,9) and C(2,7,9) be the vertices of a triangle.The internal bisector of the angle A meets BC at the point D. Find the coordinates of D.

A (3, 2, 0), B(5, 3, 2), C(- 9, 6, -3) are three points forming a triangle. AD, the bisector of anlge BAC meets [BC] at D. Find the co-ordinates of D.

Let (4, 2), B (6, 5) and C (1, 4) be the vertices of triangleABC . :- The median from A meets BC at D. Find the coordinates of the point D.

A(1,3) and C(-2/5, -2/5) are the vertices of a triangle ABC and the equation of the internal angle bisector of angleABC " is " x+y=2. The coordinates of vertex B are

Let A(1, 2, 3), B(0, 0, 1) and C(-1, 1, 1) are the vertices of triangleABC . Q. The equation of internal angle bisector through A to side BC is

If A(-1, 6), B(-3, -9) and C(5, -8) are the vertices of a triangle ABC , find the equations of its medians.

The points A(4, 5, 10), B(2, 3, 4) and C(1, 2, -1) are three vertices of a parallelogram ABCD. Find the vector equations of side AB and BC and also find the coordinates of point D .

ABC is a right angled with AB=AC. Bisector of angleA meets BC at D. prove that BC=2AD

Let A (4, 2), B (6, 5) and C (1, 4) be the vertices of triangleABC . :- Find the coordinates of the point P on AD such that AP : PD = 2:1

Are the points A (3, 6, 9), B (10, 20, 30) and C (25,- 41, 5) the vertices of a right-angled triangle ?