Find `dy/dx` when `x = a sec theta, y = b tan theta`.

If x and y are connected parametrically by the equations given in Exercises 1 to 10, without eliminating the parameter, Find dy/dx : x = a sec theta, y = b tan theta

If x and y are connected parametrically by the equation , without eliminating parameter , find dy/dx x = a sec(theta) , y = b tan(theta)

Find (dy)/(dx) in the following x = a sec theta, y = b tan theta .

Find dy/dx when x = a (cos theta + theta sin theta) , y = a (sin theta - theta cos theta).

If x and y are connected parametrically by the equations given in Exercises 1 to 10, without eliminating the parameter, Find dy/dx : : x = a cos theta, y = b cos theta

Find dy/dx , if x and y are connected parametrically by the equations (without eliminating the parameter). x = a sec theta, y = b tan theta .

Find dy/dx when y = tan (x+y)

Eliminate theta between the equation : x =a sec theta, y= b tan theta .

Find dy/dx when x = cos theta + cos 2 theta, y = sin theta + sin 2 theta)