An open cubical tank `(10m times10m times10m)` is `(2)/(3)rd` filled with water.Find the volume of water that came out of the tank.If it is accelerated with an acceleration of `2.0m/sec^(2)`.`(g=10m/sec^(2))`

In a given figure the acceleration of M is (g=10ms^(-2))

Calculate the work done in lifting a 300N weight to a height of 10m with an acceleration 0.5ms^(-2) . Take g= 10ms^(-2) .

A closed rectangular tank 10 m long, 5 m wide and 3 m deep is completely filled with an oil of specific gravity 0.92 . Find the pressure difference between the rear and front corners of the tank, if it is moving with an acceleration of 3m//s^(2) in the horizontal direction.

Find, volume of a cube of side a = 1.4 xx (10^-2) m.

(b) A 10 kg weight is raised to a height of 2.0 m with an acceleration of 1.5 m//s^(2) . Compute the work done, if g=10 m//s^(2) .

A block of mass 1 kg and density 0.8g//cm^(3) is held stationary with the help of a string as shown in figure. The tank is accelerating vertically upwards with an acceleration a =1.0m//s^(2) . Find (a) the tension in the string, (b) if the string is now cut find the acceleration of block. (Take g=10m//s^(2) and density of water =10^(3)kg//m^(3)) .

A simple pendulum 4 m long swings with an amplitude of 0.2 m. What is its acceleration at the ends of its path? (g = 10m//s^(2) )

A pendulum suspended from the ceiling of the train has a time period of two seconds when the train is at rest, then the time period of the pendulum, if the train accelerates 10 m//s^(2) will be (g=10m//s^(2))

A spherical tank of 1.2 m radius is half filled with oil of relative density 0.8 . If the tank is given a horizontal acceleration of 10 m//s^(2) , the maximum pressure on the tank is sqrt(2P) pascal. Find the value of P .

A mass m of volume V=10cm^(2) is tied with a string to the base of a container filled with a liquid of density (P_(l)=10^(3)kg//m^(3)) as shown in the figure. The container is then accelerated with acceleration (a_(x)=9m//s^(2)) and (a_(y)=2m//s^(2)) a shown in the figure. [ g=10((m)/(s^(2))) acceleration due to gravity] the net buoyancy force acting on the mass is