A resistance of 20Ω is connected to a source of alternating current rated 110V,50Hz. Then the time taken by the current to changes from its maximum value to the r.m.s. value is

A resistance of 20ohms is connected to a source of an alternating potential V=220sin(100pit) . The time taken by the current to change from its peak value to r.m.s. value is

A resistance of 20ohms is connected to a source of an alternating potential V=220sin(100pit) . The time taken by the current to change from its peak value to r.m.s. value is

A resistance of 20 Omega is connected to a source of an alternating potential V=220 sin (100 pi t) . The time taken by the current to change from the peak value to rms value is

A resistance of 20 Omega is connected to a source of alternating current rated 110 V, 50 Hz . Find (a) the rms current, (b) the maximum instantaneous current in the resistor and (c) the time taken by the current to change from its maximum value to the rms value.

An AC source is rated at 220V, 50 Hz. The time taken for voltage to change from its peak value to zero is

The electric current in an AC circuit is given by I=I_(0)sin omegat .What is the time taken by the current to change from its maximum value to the rms value?

The frequency of an alternating current is 50 Hz . The minimum time taken by it is reaching from zero to peak value is

The rms value of an ac of 50Hz is 10A. The time taken by an alternating current in reaching from zero to maximum value and the peak value will be

The root-mean-square value of an alternating current of 50 Hz frequency is 10 ampere. The time taken by the alternating current in reaching from zero to maximum value and the peak value of current will be

The time required for a 50 Hz sinusoidal alternating current to changed its value from zero to the r.m.s. value