If the sides if `triangleABC` are 5,7,8 units, then `AG^2+BG^2+CG^2` is equal to (G=Centriod)

In a triangleABC , bc=a, a=2, the value of 2DeltaR is equal to

In triangleABC , if ar (triangleABC)=8 . Then, a^(2)sin(2B)+ b^(2)sin(2A) is equal to

The mid-points of the sides of a triangle are (2,1),(-5,7) and (-5,-5)dot Find the equations of the sides of the triangle.

The mid points of the sides of a triangle are (5, 7, 11), (0, 8, 5) and (2 ,3,-1) Find its vertices and hence find centroid.

If D(-2, 3), E (4, -3) and F (4, 5) are the mid-points of the sides BC, CA and AB of the sides BC, CA and AB of triangle ABC, then find sqrt((|AG|^(2)+|BG|^(2)-|CG|^(2))) where, G is the centroid of Delta ABC .

In triangleABC , if R/r le 2 , and a=2, then triangle is equal to (triangle=ar(triangleABC)) .

If two sides of a triangle are roots of the equation x^2-7x+8=0 and the angle between these sides is 60^0 then the product of inradius and circumradius of the triangle is 8/7 (b) 5/3 (c) (5sqrt(2))/3 (d) 8

If, in a triangleABC, tan(A/2) =5/6 and tan(C/2) = 2/5 , then:

If the points A (2,9), B (a,5) and C (5,5) are the vertices of a triangleABC . Right-angled at B, then find the values of a and hence the area of triangleABC .

Let A(1, 2, 3), B(0, 0, 1) and C(-1, 1, 1) are the vertices of triangleABC . Q. The area of (triangleABC) is equal to