Evaluate `int sin^(6)theta cos^(3)theta d theta`

int (sin theta + cos theta) * d theta

Evaluate int((2 sin theta + sin 2 theta)d theta)/((cos theta-1)sqrt(cos theta + cos^(2) theta + cos^(3) theta)) .

int(sin^(3)theta)/(sqrt(cos theta))d theta

Evaluate: int cos2 theta ln((cos theta+sin theta)/(cos theta-sin theta))d theta

int(sin^(6)theta+cos^(6)theta)/(sin^(2)theta cos^(2)theta)d theta=

int(tan(2 theta))/(sqrt(sin^(6)theta+cos^(6)theta))d theta

int(2sin theta cos theta)/(sin^(4)theta+cos^(4)theta)d theta

If int(sin3 theta+sin theta)cos theta e^(sin theta)dth eta=(A sin^(3)theta+B cos^(2)theta+C sin theta+D cos theta+E)e^(sin theta)+F ,then

int_ (0) ^ ((pi) / (2)) (sin2 theta) / (sin ^ (4) theta + cos (4) theta) d theta