The number of molecules present in 1.12×`10 ^(−7)` cc of a gas at STP is:

The maximum number of molecules is present in

The maximum number of molecules is present in :

Number of atoms present in 224 dm^(3) of oxygen gas at STP is :-

Avogadro's law states that under similar condition of T and P, equal number of particles. Experiments show that at one atmosphere pressure and at a temperature 273 K (i.e. at STP) one mole of any gas occupy a volume approximately 22.4 litre. Therefore number of moles of any sample of gas can be found by comparing its volume at STP with 22.4. 1 mole of any species contains 6.023xx10^(23) particles which is denoted by symbol N_(A) . Number of atoms present in 1 gm-atom of an element or number of molecules present in 1 gm-molecule of any substance is equal to N_(A) . Hence it is number of particles present in one mole of the substance. If N_(AV) is Avogardo's number, then 10 amu will be equal to _________ gram.

Calculate the number of nitrogen molecules present in 2.8 g of nitrogen gas.

Find the number of moles and molecules present in 7.1 g of Cl_(2). (At Wt. Cl = 35.5)

Calculate the number of molecules in 1 cc of an ideal gas at 27^(@)C a pressure of 10 mm of mercury. Mean kinetic energy of molecule at 27^(@)C is 4 xx 10^(-14) erg, the density of mercury is 13.6 g//cc .

Calcualte the number of molecules in 5.6 litres of a gas at STP

At 30^(@)C and 720 mm of Hg, the density of a gas is 1.5 g// l t . Calculate molecular mass of the gas. Also find the number of molecules in 1 cc of the gas at the same temperature.

Number of neutrons present in 1.7 grams of ammonia is-