If `0.30` mole of `CaCl_(2)` is mixed with `0.20` mole of `Na_(3)PO_(4)`, the maximum number of moles of `Ca_(3)(PO_(4))_(2)` which can be formed, is:

If 0.50 mol of BaCl_(2) is mixed with 0.20 mol of Na_(3)PO_(4) , the maximum number of moles of Ba_(3)(PO_(4))_(2) that can be formed is

Ca_(3)(PO_(4))_(2) is :

Ca_(3)(PO_(4))_(2) is :

If 0.5 mole of BaCl_(2) mixed with 0.20 mole of Na_(3) PO_(4) the maximum number of moles of Ba_(3)(PO)_(2) then can be formed is

If 0.5 mole of BaCl_(2) is mixed with 0.20 mole of Na_(3)PO_(4) , the maximum number of Ba_(3)(PO_(4))_(2) that can be formed is :

If 0.5 mol of CaBr_(2) is mixed with 0.2 mol of K_(3) PO_(4) , the maximum nubmer of moles of Ca_(3) (PO_(4))_(2) that can be formed is: a. 0.1 b. 0.2 c. 0.5 d.0.7

0.5 mole of H_(2)SO_(4) is mixed with 0.2 mole of Ca(OH)_(2) . The maximum number of mole of CaSO_(4) formed is:

Ca_(3)(PO_(4))_(2) is presents in bones.

How many moles of Na^(+) ions are in 20mL "of" 0.40" "M " "Na_(3)PO_(4) .

How many moles of NaOH is required to neutralize 1 mole of H_(3)PO_(3)